Topic: Oracle Certified Professional Exams (OCP & OCA) >> Question about count distinct (Q116 in TK) 1Z0-007
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| Title: Question about count distinct (Q116 in TK) 1Z0-007 |
| ozkucur |
Posted: Nov 07, 2006 05:08:06 AM |
Total Post: 23
Joined: Oct, 2006
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The CUSTOMERS table has these columns:
CUSTOMER_ID
CUSTOMER_NAME
STREET_ADDRESS
CITY_ADDRESS
NUMBER (4)
VARCHAR2 (100)
VARCHAR2 (150)
VARHCAR2 (50)
NOT NULL
NOT NULL
STATE_ADDRESS VARCHAR2 (50)
PROVINCE_ADDRESS VARCHAR2 (50)
COUNTRY_ADDRESS VARCHAR2 (50)
POSTAL_CODE VARCHAR2 (12)
CUSTOMER_PHONE VARCHAR2 (20)
The CUSTOMER_ID column is the primary key for the table.
You need to determine how dispersed your customer base is.
Which expression finds the number of different countries represented in the
CUSTOMERS table?
A)COUNT(UPPER(country_address))
B)COUNT(DIFF(UPPER(country_address)))
C)COUNT(UNIQUE(UPPER(country_address)))
D)COUNT DISTINTC UPPER(country_address)
E)COUNT(DISTINTC (UPPER(country_address)))
ANSWER: TK says E
IMO: C
It is obvious that the DISCTINCT keyword mistyped in the D and E options. I don't know if it is intentionally done or the guy who braindumped the question just mistyped it.
Apart from that, although it is not mentioned in the (my) SQL books, I have surprisingly realised that, one use the UNIQUE keyword can be used instead of the DISTINCT keyword in count function. And it produces the same result.
E.g.:
The following two statements produced the same result in the HR schema
select count(DISTINCT(UPPER(last_name))) from employees
select count(UNQIUE(UPPER(last_name))) from employees
Any comments? |
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 snehalatha |
| Posted: Nov 07, 2006 05:29:36 AM |  |
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Total Post: 169
Joined: Apr, 2006
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C is CORRECT ANSWER.
UNIQUE will generate the same result as DISTINCT.
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| ozkucur |
| Posted: Nov 07, 2006 05:32:17 AM | |
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Total Post: 23
Joined: Oct, 2006
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| Time Zone: EDT |
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